The disk's status has always had a bit meaning "still going", and the header
beside it has always said to honour it. Nothing did, because nothing could: the
host finished the transfer inside the instruction that asked for it, so the bit
could never be seen up and asking about it was asking about something that
cannot happen.
--disk-cycles gives it a latency. The command is still checked at once, because
a refusal is not work - a block that is not there fails before any head moves -
but the transfer is remembered and done when the machine has run that far. Until
then the buffer holds the block BEFORE this one.
That last part is the point. A program that does not wait gets the wrong bytes
rather than an error, which is the failure the bit exists to prevent and the one
that would never have shown up. With a latency of two thousand, CosmOS could not
even mount: sbfsMount reads block zero and looks straight at the buffer.
deviceTick is the general shape rather than a disk feature. Called once per
instruction with the machine's clock, it lets anything whose moment has come
finish - which is what a display that refreshes, or a port that waits on the
host, would want in exactly the same way.
The filesystem watches the bit now, in one small routine reached with RCAL. That
is not decoration: what it hands back is the settled status in A, and CALL puts A
back the way it found it, so an ordinary call cannot carry the one thing this
exists to carry. Two bytes of Stack rather than ten, in a routine that runs on
every block the machine ever touches - the first place in the system where the
new call is the right one rather than merely a cheaper one.
The manifest takes a @N after a disk, the way it already takes :ro, so a test can
ask for a slow one. cosmosSlowDisk lists a directory at two thousand cycles a
block and gets the same listing as everything else, which is the whole assertion:
a filesystem that did not wait would print nonsense rather than fail.
Zero is the default and every other test runs at it. What waiting costs, on a
directory heavy run: 229k cycles at zero, 275k at five hundred, 415k at two
thousand, 1.16M at ten thousand.
Co-Authored-By: Claude Opus 5 <noreply@anthropic.com>
Claude-Session: https://claude.ai/code/session_01E2JrLzFvuFX9fgi1LDRjrW
cycleCount used to tick once per instruction, so RSTA cost what SETD cost and a
CALL moving ten bytes of Stack cost what a branch cost. No machine anybody could
build works that way, and the emulator's job is to be the thing the hardware is
designed against.
Every touch of memory now goes through one of four accessors that charge for it:
fetching an opcode, fetching the bytes after it, reading or writing Data Memory,
and reaching a device port. One access, one cycle, nothing overlapped. The
accessors exist so the cost is counted where the access happens rather than in a
table of per instruction costs kept somewhere else - a table like that is a
second copy of what the code does, and the two drift.
The run loop spends a budget of cycles instead of running a count of
instructions, so the emulated rate means something: an instruction costs what it
touches, and a batch ends when the cycles are gone.
What the numbers say now: RSTA 1 and SETD 4, being one byte and four. LDA 3,
DPUA 2. CALL and RET together 24, RCAL and RRET together 8, because the first
pair moves twenty bytes of Stack and the second moves four. The average SplitBit
instruction costs 3.72 of these, measured over the native assembler assembling a
program.
And the measurement that prompted all of this: converting the filesystem's
hottest leaf routine to RCAL is 3.1 per cent cheaper on a directory heavy
workload. The old model said 0.0, which is what a model that cannot see memory
traffic must say about a change that is nothing else.
Three tests moved. settle() strips the cycle count from recorded output, so
nothing should have churned - but it was anchored to the start of a line and
replCalculator's last output has no newline on it, which leaves the halt message
mid line where the pattern never reached. Not anchored any more.
The two Life programs are bounded by a cycle count because they never end, and
that number was rescaled from 3,000,000 to 11,200,000 - the same amount of work
at 3.72 cycles to the instruction. Nothing about either program changed. No limit
reproduces the old output exactly, because the cut now lands elsewhere in a
frame, so they are recorded again rather than tuned to match.
Whether hardware overlaps a fetch with the end of the previous instruction is
left open on purpose. This is the conservative model; pipelining is a decision to
make while drawing the hardware, not one to inherit from an emulator.
Co-Authored-By: Claude Opus 5 <noreply@anthropic.com>
Claude-Session: https://claude.ai/code/session_01E2JrLzFvuFX9fgi1LDRjrW
AnachronautandClaude Opus 5