CosmOS had 1,161 bytes of Program Memory left before the address applications load at, and Tab completion is not going to fit in that with anything to spare. So the wall moves up one page: the system keeps below 0x4FFF and 0x2FFF, and an application is based at 0x5000 and 0x3000. A PAGE IS A CHEAP THING TO GIVE IT AND AN EXPENSIVE THING TO RUN OUT OF. An application still has 44K of Program Memory before the vector table and the largest one here uses 7.5K, so what was taken from applications is space nothing has ever asked for - while what the system gained is the difference between building the next thing and counting bytes while building it. Not doubling, which was the version that would have cost application space worth minding. One page, and the same again when it is needed. Nothing in the machine knows where the wall is, so this is 34 #Base lines, one threshold in the fault handler, and the table in the CosmOS README that Tests/docs.sh reads its limits out of. The native assembler's scratch map had to move with it, and docs.sh said so before anything ran: its data reached 0x40D6 and its buffers began at 0x4000, so they were sitting on its variables. That file already carries a paragraph about the floor coming up and the map staying where it was. It has happened twice now, and been caught by a check the first time wrote. Twenty three recordings are the same runs a page higher. Co-Authored-By: Claude Opus 5 <noreply@anthropic.com> Claude-Session: https://claude.ai/code/session_01E2JrLzFvuFX9fgi1LDRjrW
277 lines
4.4 KiB
NASM
277 lines
4.4 KiB
NASM
; Copy one file to another without asking either file to fit in Data Memory.
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;
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; The two paths are the two words in the argument. Filesystem names can contain spaces,
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; but the CosmOS command line has no quoting yet, so this deliberately has the same rule
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; as the shell: a space separates things.
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;
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; osFileInfo reports how many disk blocks the source occupies, while osFileStart wants the
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; shape stored in an SBFS entry: whole blocks and a possible tail. Reading the last block
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; first recovers that distinction. The ordinary copy then walks forward one block at a
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; time, through one 256-byte buffer.
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;
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; Written by ChatGPT for Anachronaut's SplitBit
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#Include services.asm
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#Program
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#Base 0x5000
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start:
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SETD.0 Arguments
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INIB 0xFF
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SWI osArgument
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SETD.0 Arguments
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LDA.0
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BRA usage
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CALL textSplit
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SETD.0 TextRest
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LDD.0.0
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LDA.0
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BRA usage
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; How many occupied blocks the source has. Keep it as both the loop bound and the
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; distinction between an empty file and one whose last block must be inspected.
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SETD.0 Arguments
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SWI osFileInfo
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BNQ sourceFailed
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SETD.0 SourceBlocks
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STD.3.0
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PSHD.3
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POPB
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POPA
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OR
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BRQ emptySource
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; Read the final occupied block. DP3 says how many bytes of it belong to the file:
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; 0x0100 for a whole block, or 0x0001 through 0x00FF for a tail.
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SETD.0 SourceBlocks
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LDD.3.0
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DECD.3
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SETD.0 Index
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STD.3.0
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SETD.0 Arguments
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SETD.1 Block
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SETD.2 Index
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LDA.2
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INCD.2
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LDB.2
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SWI osFileBlock
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BNQ readFailed
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SETD.0 LastCount
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STD.3.0
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; A full final block means every occupied block is whole. A short final block means
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; there is one fewer whole block and its low-byte count is the tail.
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SETD.0 LastCount
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LDA.0
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BNA wholeEnding
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SETD.0 Index
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SETD.1 OutputWhole
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CALL copyWord
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SETD.0 LastCount
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INCD.0
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LDA.0
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SETD.1 OutputTail
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STA.1
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BRI sizeKnown
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wholeEnding:
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SETD.0 SourceBlocks
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SETD.1 OutputWhole
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CALL copyWord
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RSTA
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SETD.0 OutputTail
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STA.0
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sizeKnown:
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BRI startOutput
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emptySource:
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RSTA
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SETD.0 OutputWhole
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STA.0
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INCD.0
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STA.0
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SETD.0 OutputTail
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STA.0
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startOutput:
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SETD.0 TextRest
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LDD.0.0
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SETD.2 OutputWhole
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LDD.3.2
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SETD.2 OutputTail
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LDA.2
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SWI osFileStart
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BNQ startFailed
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; Empty files have no blocks to transfer, but still need committing so that an existing
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; destination becomes an empty file.
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SETD.0 SourceBlocks
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SETD.1 RemainingBlocks
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CALL copyWord
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RSTA
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SETD.0 Index
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STA.0
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INCD.0
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STA.0
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copyNext:
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SETD.0 RemainingBlocks
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LDA.0
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INCD.0
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LDB.0
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OR
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BRQ copyDone
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SETD.0 Arguments
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SETD.1 Block
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SETD.2 Index
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LDA.2
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INCD.2
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LDB.2
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SWI osFileBlock
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BNQ readFailed
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SETD.1 Block
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SETD.2 Index
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LDA.2
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INCD.2
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LDB.2
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SWI osFileWrite
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BNQ writeFailed
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CALL stepIndex
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CALL takeBlock
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BRI copyNext
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copyDone:
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SETD.2 OutputWhole
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LDD.3.2
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SETD.2 OutputTail
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LDA.2
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SWI osFileDone
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BNQ doneFailed
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SETD.0 Copied
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SWI osPrintString
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RSTA
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SWI osExit
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; DP0 names the source word and DP1 the destination word.
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copyWord:
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LDA.0
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STA.1
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INCD.0
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INCD.1
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LDA.0
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STA.1
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RET
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; Increment the big-endian sixteen-bit Index.
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stepIndex:
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SETD.0 Index
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INCD.0
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LDA.0
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INCA
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STA.0
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BNC stepDone
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DECD.0
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LDA.0
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INCA
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STA.0
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stepDone:
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RET
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; Decrement the big-endian sixteen-bit RemainingBlocks.
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takeBlock:
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SETD.0 RemainingBlocks
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INCD.0
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LDA.0
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BRA takeBorrow
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DECA
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STA.0
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RET
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takeBorrow:
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INIA 0xFF
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STA.0
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DECD.0
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LDA.0
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DECA
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STA.0
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RET
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usage:
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SETD.0 Usage
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SWI osPrintString
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INIA 0d2
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SWI osExit
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sourceFailed:
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SETD.0 SourceError
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SWI osPrintString
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INIA 0d1
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SWI osExit
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readFailed:
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SETD.0 ReadError
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SWI osPrintString
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INIA 0d1
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SWI osExit
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startFailed:
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SETD.0 StartError
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SWI osPrintString
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INIA 0d1
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SWI osExit
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writeFailed:
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SETD.0 WriteError
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SWI osPrintString
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INIA 0d1
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SWI osExit
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doneFailed:
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SETD.0 DoneError
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SWI osPrintString
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INIA 0d1
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SWI osExit
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#Data
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#Base 0x3000
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Arguments:
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#Reserve 0d256
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SourceBlocks:
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0x00 0x00
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RemainingBlocks:
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0x00 0x00
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Index:
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0x00 0x00
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LastCount:
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0x00 0x00
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OutputWhole:
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0x00 0x00
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OutputTail:
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0x00
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Block:
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#Reserve 0d256
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Usage:
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"copy: give me a source and destination
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"
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SourceError:
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"copy: cannot find the source
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"
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ReadError:
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"copy: cannot read the source
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"
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StartError:
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"copy: cannot create the destination
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"
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WriteError:
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"copy: cannot write the destination
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"
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DoneError:
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"copy: cannot finish the destination
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"
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Copied:
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"copied
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"
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#Include text.asm
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